ICCF



SWE Peter Winberg (2200 Provisional)
   

          
          
          
          
          
          
          
          
 
1.d4 d6 2.c4 Nf6 3.Nc3 Nbd7 4.Nf3 e5 5.e4 exd4 6.Nxd4 g6 7.Be2 Bg7 8.O-O O-O 9.f3 a5 10.Be3 Nc5 11.Ndb5 b6 12.e5 Ne8 13.f4 Be6 14.Qe1 dxe5 15.Rd1 Nd6 16.fxe5 Bxe5 17.Bd4 Qg5 18.Bxe5 Qxe5 19.Nxc7 Rad8 20.Nxe6 fxe6 21.Rxf8+ Rxf8 22.Bf1
1/2-1/2

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LAT Guntis Gerhards (2091)
 

     

 


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