ICCF



SWE Per Nyberg (1800 Provisional)
   

          
          
          
          
          
          
          
          
 
1.e4 e5 2.Nf3 Nc6 3.Nc3 Nf6 4.Bc4 Bc5 5.O-O d6 6.Re1 O-O 7.h3 Nd4 8.Nxd4 Bxd4 9.d3 Be6 10.Bxe6 fxe6 11.Be3 c5 12.Bxd4 cxd4 13.Ne2 Rc8 14.c3 dxc3 15.bxc3 Qc7 16.Rc1 Qf7 17.Ng3
1/2-1/2

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USA William J. Lindberg (1466)
 

     

 


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